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UDHY :3 Jumat, 31 Agustus 2012 0 notes
1. a. luas = 2992   v = 12.320   
    b. luas = 4270,4 v= 17600
    c. luas= 4675 v= 24.062, 5
2. a. keliling alas kerucut = keliling sektor                                      
    288/360 x 2phi x r = 2phi x r ---> 2 phi sama jd dicoret
    288/360 x 40 = r
     32 = r

     t = s pangkat 2 - r pangkat 2 diakar
       = 40 pangkat 2 - 32 pangkat 2 diakar
       = 24 cm
    b. volume = 1/3 phi r kuadrat x t
                    = 25.722,88 cm kubik
    c. phi x r (r+s) = 7.234,56
3. a. luas= 4phi x r kuadrat     v= 4/3 x phi x r pangkat 3
       = 15400
    b. luas= 20.096 v= 267.946,67
4. a) selimut kerucut = phi kali r kali s = 565,2
    tab = 2 x phi x r x t + phi kali r kuadrat = 1205, 76
    selimut kerucut + tabung = 1770,96
  b) aku bingung ._. ini ditambah apa dikurang apa yaapa ._.
5. aku masih mbulet let let let ._. jawabanku gk sama kayak pak tahid ._.



   
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